Base | Representation |
---|---|
bin | 11101001011100101… |
… | …111010010011100111 |
3 | 2222212122120100012011 |
4 | 131023211322103213 |
5 | 1003132222003143 |
6 | 22221050535051 |
7 | 2156314052314 |
oct | 351345722347 |
9 | 88778510164 |
10 | 31333000423 |
11 | 12319730a7a |
12 | 60a5437487 |
13 | 2c545b594a |
14 | 17334b9d0b |
15 | c35b86e9d |
hex | 74b97a4e7 |
31333000423 has 4 divisors (see below), whose sum is σ = 31333840120. Its totient is φ = 31332160728.
The previous prime is 31333000417. The next prime is 31333000429. The reversal of 31333000423 is 32400033313.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (31333000417) and next prime (31333000429).
It is a cyclic number.
It is not a de Polignac number, because 31333000423 - 29 = 31332999911 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 31333000394 and 31333000403.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31333000429) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 361140 + ... + 439417.
It is an arithmetic number, because the mean of its divisors is an integer number (7833460030).
Almost surely, 231333000423 is an apocalyptic number.
31333000423 is a deficient number, since it is larger than the sum of its proper divisors (839697).
31333000423 is an equidigital number, since it uses as much as digits as its factorization.
31333000423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 839696.
The product of its (nonzero) digits is 1944, while the sum is 22.
Adding to 31333000423 its reverse (32400033313), we get a palindrome (63733033736).
The spelling of 31333000423 in words is "thirty-one billion, three hundred thirty-three million, four hundred twenty-three", and thus it is an aban number.
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