Base | Representation |
---|---|
bin | 101101100110000111110… |
… | …101101011101100011111 |
3 | 102002112121202211211211200 |
4 | 231212013311223230133 |
5 | 402314004344434201 |
6 | 10355231154450543 |
7 | 442242226611522 |
oct | 55460765535437 |
9 | 12075552754750 |
10 | 3133310155551 |
11 | aa8913996754 |
12 | 42730b293a53 |
13 | 199615431354 |
14 | ab91dc62bb9 |
15 | 56787eb4386 |
hex | 2d987d6bb1f |
3133310155551 has 12 divisors (see below), whose sum is σ = 4602602489160. Its totient is φ = 2053468802160.
The previous prime is 3133310155489. The next prime is 3133310155579. The reversal of 3133310155551 is 1555510133313.
3133310155551 is a `hidden beast` number, since 3 + 13 + 33 + 10 + 1 + 55 + 551 = 666.
It is not a de Polignac number, because 3133310155551 - 221 = 3133308058399 is a prime.
It is a super-2 number, since 2×31333101555512 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3133310155951) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2950385680 + ... + 2950386741.
It is an arithmetic number, because the mean of its divisors is an integer number (383550207430).
Almost surely, 23133310155551 is an apocalyptic number.
3133310155551 is a deficient number, since it is larger than the sum of its proper divisors (1469292333609).
3133310155551 is a wasteful number, since it uses less digits than its factorization.
3133310155551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5900772486 (or 5900772483 counting only the distinct ones).
The product of its (nonzero) digits is 50625, while the sum is 36.
Adding to 3133310155551 its reverse (1555510133313), we get a palindrome (4688820288864).
The spelling of 3133310155551 in words is "three trillion, one hundred thirty-three billion, three hundred ten million, one hundred fifty-five thousand, five hundred fifty-one".
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