3133340433313 has 4 divisors (see below), whose sum is σ = 3161069109828. Its totient is φ = 3105611756800.

The previous prime is 3133340433299. The next prime is 3133340433371.

3133340433313 is nontrivially palindromic in base 10.

3133340433313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1146627631249 + 1986712802064 = 1070807^2 + 1409508^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3133340433313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3133340403313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13864338088 + ... + 13864338313.

It is an arithmetic number, because the mean of its divisors is an integer number (790267277457).

Almost surely, 2^{3133340433313} is an apocalyptic number.

It is an amenable number.

3133340433313 is a deficient number, since it is larger than the sum of its proper divisors (27728676515).

3133340433313 is a wasteful number, since it uses less digits than its factorization.

3133340433313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27728676514.

The product of its (nonzero) digits is 104976, while the sum is 34.

It can be divided in two parts, 3133340 and 433313, that added together give a palindrome (3566653).

The spelling of 3133340433313 in words is "three trillion, one hundred thirty-three billion, three hundred forty million, four hundred thirty-three thousand, three hundred thirteen".