Base | Representation |
---|---|
bin | 101101100110111000001… |
… | …111110111001000111111 |
3 | 102002121201101002022020201 |
4 | 231212320033313020333 |
5 | 402322140303341133 |
6 | 10355443530224331 |
7 | 442301321130250 |
oct | 55467017671077 |
9 | 12077641068221 |
10 | 3134122324543 |
11 | aa91a03892a1 |
12 | 4274b72850a7 |
13 | 199714785112 |
14 | ab999a78b27 |
15 | 567d4441d7d |
hex | 2d9b83f723f |
3134122324543 has 4 divisors (see below), whose sum is σ = 3581854085200. Its totient is φ = 2686390563888.
The previous prime is 3134122324537. The next prime is 3134122324559. The reversal of 3134122324543 is 3454232214313.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3134122324543 - 233 = 3125532389951 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3134122324513) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223865880318 + ... + 223865880331.
It is an arithmetic number, because the mean of its divisors is an integer number (895463521300).
Almost surely, 23134122324543 is an apocalyptic number.
3134122324543 is a deficient number, since it is larger than the sum of its proper divisors (447731760657).
3134122324543 is an equidigital number, since it uses as much as digits as its factorization.
3134122324543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 447731760656.
The product of its digits is 207360, while the sum is 37.
Adding to 3134122324543 its reverse (3454232214313), we get a palindrome (6588354538856).
The spelling of 3134122324543 in words is "three trillion, one hundred thirty-four billion, one hundred twenty-two million, three hundred twenty-four thousand, five hundred forty-three".
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