Base | Representation |
---|---|
bin | 100011101000011000010011… |
… | …1001001011111101011101011 |
3 | 1112002200222202120020102201210 |
4 | 1013100300213021133223223 |
5 | 312034424321120333303 |
6 | 3030323541013244203 |
7 | 123005225365210026 |
oct | 10720604711375353 |
9 | 1462628676212653 |
10 | 313413010324203 |
11 | 90954790738769 |
12 | 2b19965b033663 |
13 | 105b5948c7654a |
14 | 57573b08b61bd |
15 | 26378d1bd0203 |
hex | 11d0c2725faeb |
313413010324203 has 4 divisors (see below), whose sum is σ = 417884013765608. Its totient is φ = 208942006882800.
The previous prime is 313413010324201. The next prime is 313413010324207. The reversal of 313413010324203 is 302423010314313.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 313413010324203 - 21 = 313413010324201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (313413010324201) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52235501720698 + ... + 52235501720703.
It is an arithmetic number, because the mean of its divisors is an integer number (104471003441402).
Almost surely, 2313413010324203 is an apocalyptic number.
313413010324203 is a deficient number, since it is larger than the sum of its proper divisors (104471003441405).
313413010324203 is a wasteful number, since it uses less digits than its factorization.
313413010324203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104471003441404.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 313413010324203 its reverse (302423010314313), we get a palindrome (615836020638516).
The spelling of 313413010324203 in words is "three hundred thirteen trillion, four hundred thirteen billion, ten million, three hundred twenty-four thousand, two hundred three".
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