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3134404035 = 32579950489
BaseRepresentation
bin1011101011010011…
…0011010111000011
322002102221020000100
42322310303113003
522404401412120
61235005053443
7140446665120
oct27264632703
98072836010
103134404035
111369320164
12735857283
133ac4b2759
1421a3d1747
15135292490
hexbad335c3

3134404035 has 24 divisors (see below), whose sum is σ = 6209105760. Its totient is φ = 1432870272.

The previous prime is 3134403997. The next prime is 3134404037. The reversal of 3134404035 is 5304044313.

It is not a de Polignac number, because 3134404035 - 27 = 3134403907 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3134404037) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4974930 + ... + 4975559.

It is an arithmetic number, because the mean of its divisors is an integer number (258712740).

Almost surely, 23134404035 is an apocalyptic number.

3134404035 is a gapful number since it is divisible by the number (35) formed by its first and last digit.

3134404035 is a deficient number, since it is larger than the sum of its proper divisors (3074701725).

3134404035 is a wasteful number, since it uses less digits than its factorization.

3134404035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9950507 (or 9950504 counting only the distinct ones).

The product of its (nonzero) digits is 8640, while the sum is 27.

The square root of 3134404035 is about 55985.7484990600. The cubic root of 3134404035 is about 1463.4739372902.

Adding to 3134404035 its reverse (5304044313), we get a palindrome (8438448348).

The spelling of 3134404035 in words is "three billion, one hundred thirty-four million, four hundred four thousand, thirty-five".

Divisors: 1 3 5 7 9 15 21 35 45 63 105 315 9950489 29851467 49752445 69653423 89554401 149257335 208960269 348267115 447772005 626880807 1044801345 3134404035