Base | Representation |
---|---|
bin | 101101100111001111011… |
… | …011000000000010101001 |
3 | 102002122201110200012002221 |
4 | 231213033123000002221 |
5 | 402323434321324203 |
6 | 10355550255354041 |
7 | 442314051626311 |
oct | 55471733000251 |
9 | 12078643605087 |
10 | 3134511120553 |
11 | aa937a8a150a |
12 | 4275a5522921 |
13 | 1997771a2b27 |
14 | ab9d5564441 |
15 | 56808640abd |
hex | 2d9cf6c00a9 |
3134511120553 has 4 divisors (see below), whose sum is σ = 3136619064960. Its totient is φ = 3132403176148.
The previous prime is 3134511120473. The next prime is 3134511120569. The reversal of 3134511120553 is 3550211154313.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3134511120553 - 237 = 2997072167081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3134511120953) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1053969973 + ... + 1053972946.
It is an arithmetic number, because the mean of its divisors is an integer number (784154766240).
Almost surely, 23134511120553 is an apocalyptic number.
It is an amenable number.
3134511120553 is a deficient number, since it is larger than the sum of its proper divisors (2107944407).
3134511120553 is a wasteful number, since it uses less digits than its factorization.
3134511120553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2107944406.
The product of its (nonzero) digits is 27000, while the sum is 34.
Adding to 3134511120553 its reverse (3550211154313), we get a palindrome (6684722274866).
The spelling of 3134511120553 in words is "three trillion, one hundred thirty-four billion, five hundred eleven million, one hundred twenty thousand, five hundred fifty-three".
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