Search a number
-
+
31350211151 = 74478601593
BaseRepresentation
bin11101001100100111…
…100100001001001111
32222220211221201212112
4131030213210021033
51003201123224101
622222503454235
72156613253340
oct351447441117
988824851775
1031350211151
1112328416716
1260ab15737b
132c580305cc
1417358ba0c7
15c374366bb
hex74c9e424f

31350211151 has 4 divisors (see below), whose sum is σ = 35828812752. Its totient is φ = 26871609552.

The previous prime is 31350211129. The next prime is 31350211163. The reversal of 31350211151 is 15111205313.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15111205313 = 82118405853.

It is a cyclic number.

It is not a de Polignac number, because 31350211151 - 210 = 31350210127 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31350211181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2239300790 + ... + 2239300803.

It is an arithmetic number, because the mean of its divisors is an integer number (8957203188).

Almost surely, 231350211151 is an apocalyptic number.

31350211151 is a deficient number, since it is larger than the sum of its proper divisors (4478601601).

31350211151 is an equidigital number, since it uses as much as digits as its factorization.

31350211151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4478601600.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 31350211151 its reverse (15111205313), we get a palindrome (46461416464).

The spelling of 31350211151 in words is "thirty-one billion, three hundred fifty million, two hundred eleven thousand, one hundred fifty-one".

Divisors: 1 7 4478601593 31350211151