Base | Representation |
---|---|
bin | 1110010000100001110110… |
… | …00111101001101011001111 |
3 | 11010000102210210212101020121 |
4 | 13020100323013221223033 |
5 | 13102202002244403010 |
6 | 150403540043325411 |
7 | 6414161423114650 |
oct | 710207307515317 |
9 | 133012723771217 |
10 | 31354253122255 |
11 | 9a9929a535a68 |
12 | 36247b7b20867 |
13 | 146590249169b |
14 | 7a57a8069527 |
15 | 3958e1b683da |
hex | 1c843b1e9acf |
31354253122255 has 16 divisors (see below), whose sum is σ = 43605754043904. Its totient is φ = 21197241545760.
The previous prime is 31354253122219. The next prime is 31354253122289. The reversal of 31354253122255 is 55222135245313.
It is not a de Polignac number, because 31354253122255 - 29 = 31354253121743 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6308700357 + ... + 6308705326.
It is an arithmetic number, because the mean of its divisors is an integer number (2725359627744).
Almost surely, 231354253122255 is an apocalyptic number.
31354253122255 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
31354253122255 is a deficient number, since it is larger than the sum of its proper divisors (12251500921649).
31354253122255 is a wasteful number, since it uses less digits than its factorization.
31354253122255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12617405766.
The product of its digits is 1080000, while the sum is 43.
Adding to 31354253122255 its reverse (55222135245313), we get a palindrome (86576388367568).
The spelling of 31354253122255 in words is "thirty-one trillion, three hundred fifty-four billion, two hundred fifty-three million, one hundred twenty-two thousand, two hundred fifty-five".
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