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31354400000000 = 21158711509
BaseRepresentation
bin1110010000100010000111…
…10111111100100000000000
311010000110012001020112122002
413020101003313330200000
513102202302400000000
6150404002411403132
76414165155421650
oct710210367744000
9133013161215562
1031354400000000
119a99365435430
1236248391534a8
131465926a393ac
147a57bd780360
153958ee9cc8d5
hex1c8443dfc800

31354400000000 has 864 divisors, whose sum is σ = 97896043627200. Its totient is φ = 9753600000000.

The previous prime is 31354399999987. The next prime is 31354400000017. The reversal of 31354400000000 is 445313.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 61599999746 + ... + 61600000254.

It is an arithmetic number, because the mean of its divisors is an integer number (113305606050).

Almost surely, 231354400000000 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31354400000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (48948021813600).

31354400000000 is an abundant number, since it is smaller than the sum of its proper divisors (66541643627200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31354400000000 is an frugal number, since it uses more digits than its factorization.

31354400000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 589 (or 534 counting only the distinct ones).

The product of its (nonzero) digits is 720, while the sum is 20.

Adding to 31354400000000 its reverse (445313), we get a palindrome (31354400445313).

The spelling of 31354400000000 in words is "thirty-one trillion, three hundred fifty-four billion, four hundred million", and thus it is an aban number.