Base | Representation |
---|---|
bin | 101101101001000101101… |
… | …000110011000101110011 |
3 | 102002211211200122201021111 |
4 | 231221011220303011303 |
5 | 402342020034332021 |
6 | 10400515145134151 |
7 | 442414153634110 |
oct | 55510550630563 |
9 | 12084750581244 |
10 | 3136494449011 |
11 | aaa1a8391540 |
12 | 427a5978a357 |
13 | 199a02060a71 |
14 | abb42b1d907 |
15 | 568c280d8e1 |
hex | 2da45a33173 |
3136494449011 has 16 divisors (see below), whose sum is σ = 3910551740928. Its totient is φ = 2443948459200.
The previous prime is 3136494449003. The next prime is 3136494449057. The reversal of 3136494449011 is 1109444946313.
3136494449011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 3136494449011 - 23 = 3136494449003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3136494447011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2053066 + ... + 3238528.
It is an arithmetic number, because the mean of its divisors is an integer number (244409483808).
Almost surely, 23136494449011 is an apocalyptic number.
3136494449011 is a deficient number, since it is larger than the sum of its proper divisors (774057291917).
3136494449011 is a wasteful number, since it uses less digits than its factorization.
3136494449011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1219842.
The product of its (nonzero) digits is 1119744, while the sum is 49.
The spelling of 3136494449011 in words is "three trillion, one hundred thirty-six billion, four hundred ninety-four million, four hundred forty-nine thousand, eleven".
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