Base | Representation |
---|---|
bin | 101101101001000101101… |
… | …000110011000101101011 |
3 | 102002211211200122201021012 |
4 | 231221011220303011223 |
5 | 402342020034332003 |
6 | 10400515145134135 |
7 | 442414153634066 |
oct | 55510550630553 |
9 | 12084750581235 |
10 | 3136494449003 |
11 | aaa1a8391533 |
12 | 427a5978a34b |
13 | 199a02060a66 |
14 | abb42b1d8dd |
15 | 568c280d8d8 |
hex | 2da45a3316b |
3136494449003 has 2 divisors, whose sum is σ = 3136494449004. Its totient is φ = 3136494449002.
The previous prime is 3136494448949. The next prime is 3136494449057. The reversal of 3136494449003 is 3009444946313.
3136494449003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a balanced prime because it is at equal distance from previous prime (3136494448949) and next prime (3136494449057).
It is a cyclic number.
It is not a de Polignac number, because 3136494449003 - 220 = 3136493400427 is a prime.
It is not a weakly prime, because it can be changed into another prime (3136494449063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1568247224501 + 1568247224502.
It is an arithmetic number, because the mean of its divisors is an integer number (1568247224502).
Almost surely, 23136494449003 is an apocalyptic number.
3136494449003 is a deficient number, since it is larger than the sum of its proper divisors (1).
3136494449003 is an equidigital number, since it uses as much as digits as its factorization.
3136494449003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3359232, while the sum is 50.
The spelling of 3136494449003 in words is "three trillion, one hundred thirty-six billion, four hundred ninety-four million, four hundred forty-nine thousand, three".
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