Base | Representation |
---|---|
bin | 1001001000010101010… |
… | …01100000101011110111 |
3 | 1002222202002002112111012 |
4 | 10210022221200223313 |
5 | 20114440041012201 |
6 | 400041133102435 |
7 | 31444025524364 |
oct | 4441251405367 |
9 | 1088662075435 |
10 | 313711266551 |
11 | 111053916851 |
12 | 50971327a1b |
13 | 23776685b97 |
14 | 1128013946b |
15 | 82612ab5bb |
hex | 490aa60af7 |
313711266551 has 4 divisors (see below), whose sum is σ = 313983823104. Its totient is φ = 313438710000.
The previous prime is 313711266541. The next prime is 313711266559. The reversal of 313711266551 is 155662117313.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-313711266551 is a prime.
It is a super-2 number, since 2×3137112665512 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 313711266499 and 313711266508.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (313711266559) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 136276550 + ... + 136278851.
It is an arithmetic number, because the mean of its divisors is an integer number (78495955776).
Almost surely, 2313711266551 is an apocalyptic number.
313711266551 is a deficient number, since it is larger than the sum of its proper divisors (272556553).
313711266551 is a wasteful number, since it uses less digits than its factorization.
313711266551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 272556552.
The product of its digits is 113400, while the sum is 41.
The spelling of 313711266551 in words is "three hundred thirteen billion, seven hundred eleven million, two hundred sixty-six thousand, five hundred fifty-one".
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