314000151 has 4 divisors (see below), whose sum is σ = 418666872. Its totient is φ = 209333432.

The previous prime is 314000131. The next prime is 314000153. The reversal of 314000151 is 151000413.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 314000151 - 2⁵ = 314000119 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 314000151.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (314000153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52333356 + ... + 52333361.

It is an arithmetic number, because the mean of its divisors is an integer number (104666718).

Almost surely, 2^314000151 is an apocalyptic number.

314000151 is a deficient number, since it is larger than the sum of its proper divisors (104666721).

314000151 is a wasteful number, since it uses less digits than its factorization.

314000151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104666720.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 314000151 is about 17720.0494073803. The cubic root of 314000151 is about 679.6885475381.

Adding to 314000151 its reverse (151000413), we get a palindrome (465000564).

The spelling of 314000151 in words is "three hundred fourteen million, one hundred fifty-one", and thus it is an aban number.