314003234113 has 4 divisors (see below), whose sum is σ = 314232937920. Its totient is φ = 313773530308.

The previous prime is 314003234107. The next prime is 314003234123. The reversal of 314003234113 is 311432300413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 314003234113 - 2⁵ = 314003234081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (314003234123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114849853 + ... + 114852586.

It is an arithmetic number, because the mean of its divisors is an integer number (78558234480).

Almost surely, 2^314003234113 is an apocalyptic number.

It is an amenable number.

314003234113 is a deficient number, since it is larger than the sum of its proper divisors (229703807).

314003234113 is a wasteful number, since it uses less digits than its factorization.

314003234113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 229703806.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 314003234113 its reverse (311432300413), we get a palindrome (625435534526).

The spelling of 314003234113 in words is "three hundred fourteen billion, three million, two hundred thirty-four thousand, one hundred thirteen".