Base | Representation |
---|---|
bin | 101101101100011000111… |
… | …110000010111000100111 |
3 | 102010011222210020221101102 |
4 | 231230120332002320213 |
5 | 402421300220330203 |
6 | 10402303042550315 |
7 | 442601055466316 |
oct | 55543076027047 |
9 | 12104883227342 |
10 | 3140040011303 |
11 | 10007577a8a08 |
12 | 42868906839b |
13 | 19a148790910 |
14 | abd9b97c27d |
15 | 56a2dc1a888 |
hex | 2db18f82e27 |
3140040011303 has 16 divisors (see below), whose sum is σ = 3580708400640. Its totient is φ = 2727838342656.
The previous prime is 3140040011291. The next prime is 3140040011333. The reversal of 3140040011303 is 3031100400413.
3140040011303 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 3140040011303 - 28 = 3140040011047 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3140040011333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3434426 + ... + 4251512.
It is an arithmetic number, because the mean of its divisors is an integer number (223794275040).
Almost surely, 23140040011303 is an apocalyptic number.
3140040011303 is a deficient number, since it is larger than the sum of its proper divisors (440668389337).
3140040011303 is a wasteful number, since it uses less digits than its factorization.
3140040011303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 834506.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 3140040011303 its reverse (3031100400413), we get a palindrome (6171140411716).
The spelling of 3140040011303 in words is "three trillion, one hundred forty billion, forty million, eleven thousand, three hundred three".
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