Base | Representation |
---|---|
bin | 100011101100101011101010… |
… | …0100110111001111110100011 |
3 | 1112011210112001201102202011121 |
4 | 1013121113110212321332203 |
5 | 312124121332214341003 |
6 | 3031455333115553111 |
7 | 123066031021135612 |
oct | 10731272446717643 |
9 | 1464715051382147 |
10 | 314004331012003 |
11 | 91062541864575 |
12 | 2b27418715b797 |
13 | 10629634715a58 |
14 | 5777c68181879 |
15 | 2647e8eab9cbd |
hex | 11d95d49b9fa3 |
314004331012003 has 8 divisors (see below), whose sum is σ = 314549638837200. Its totient is φ = 313459027015680.
The previous prime is 314004331011997. The next prime is 314004331012013. The reversal of 314004331012003 is 300210133400413.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 314004331012003 - 229 = 314003794141091 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (314004331012013) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 199672923 + ... + 201239371.
It is an arithmetic number, because the mean of its divisors is an integer number (39318704854650).
Almost surely, 2314004331012003 is an apocalyptic number.
314004331012003 is a deficient number, since it is larger than the sum of its proper divisors (545307825197).
314004331012003 is a wasteful number, since it uses less digits than its factorization.
314004331012003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1914437.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 314004331012003 its reverse (300210133400413), we get a palindrome (614214464412416).
The spelling of 314004331012003 in words is "three hundred fourteen trillion, four billion, three hundred thirty-one million, twelve thousand, three".
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