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31401011311 = 43730256077
BaseRepresentation
bin11101001111101001…
…010110100001101111
310000001101112122120221
4131033221112201233
51003302124330221
622231520352211
72161101122635
oct351751264157
9100041478527
1031401011311
111235406361a
126104175667
132c65708c87
14173c541355
15c3bb1d541
hex74fa5686f

31401011311 has 4 divisors (see below), whose sum is σ = 32131267432. Its totient is φ = 30670755192.

The previous prime is 31401011309. The next prime is 31401011359. The reversal of 31401011311 is 11311010413.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 31401011311 - 21 = 31401011309 is a prime.

It is a super-2 number, since 2×314010113112 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31401011111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 365127996 + ... + 365128081.

It is an arithmetic number, because the mean of its divisors is an integer number (8032816858).

Almost surely, 231401011311 is an apocalyptic number.

31401011311 is a deficient number, since it is larger than the sum of its proper divisors (730256121).

31401011311 is an equidigital number, since it uses as much as digits as its factorization.

31401011311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 730256120.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 31401011311 its reverse (11311010413), we get a palindrome (42712021724).

The spelling of 31401011311 in words is "thirty-one billion, four hundred one million, eleven thousand, three hundred eleven".

Divisors: 1 43 730256077 31401011311