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31402013403 = 3171984131033
BaseRepresentation
bin11101001111101101…
…001011001011011011
310000001110102120012110
4131033231023023123
51003302403412103
622231554043403
72161112465325
oct351755131333
9100043376173
1031402013403
11123546884a2
126104579563
132c6599a127
14173c722615
15c3bc6a403
hex74fb4b2db

31402013403 has 16 divisors (see below), whose sum is σ = 44335917216. Its totient is φ = 19701596160.

The previous prime is 31402013371. The next prime is 31402013411. The reversal of 31402013403 is 30431020413.

It is not a de Polignac number, because 31402013403 - 25 = 31402013371 is a prime.

It is a super-3 number, since 3×314020134033 (a number of 32 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 31402013403.

It is not an unprimeable number, because it can be changed into a prime (31402013003) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 996375 + ... + 1027407.

It is an arithmetic number, because the mean of its divisors is an integer number (2770994826).

Almost surely, 231402013403 is an apocalyptic number.

31402013403 is a deficient number, since it is larger than the sum of its proper divisors (12933903813).

31402013403 is a wasteful number, since it uses less digits than its factorization.

31402013403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50894.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 31402013403 its reverse (30431020413), we get a palindrome (61833033816).

The spelling of 31402013403 in words is "thirty-one billion, four hundred two million, thirteen thousand, four hundred three".

Divisors: 1 3 17 51 19841 31033 59523 93099 337297 527561 1011891 1582683 615725753 1847177259 10467337801 31402013403