Base | Representation |
---|---|
bin | 11101001111101101… |
… | …001011001010111011 |
3 | 10000001110102120011021 |
4 | 131033231023022323 |
5 | 1003302403411441 |
6 | 22231554043311 |
7 | 2161112465251 |
oct | 351755131273 |
9 | 100043376137 |
10 | 31402013371 |
11 | 12354688473 |
12 | 6104579537 |
13 | 2c6599a101 |
14 | 173c7225d1 |
15 | c3bc6a3d1 |
hex | 74fb4b2bb |
31402013371 has 2 divisors, whose sum is σ = 31402013372. Its totient is φ = 31402013370.
The previous prime is 31402013347. The next prime is 31402013411. The reversal of 31402013371 is 17331020413.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31402013371 - 27 = 31402013243 is a prime.
It is not a weakly prime, because it can be changed into another prime (31402013971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15701006685 + 15701006686.
It is an arithmetic number, because the mean of its divisors is an integer number (15701006686).
Almost surely, 231402013371 is an apocalyptic number.
31402013371 is a deficient number, since it is larger than the sum of its proper divisors (1).
31402013371 is an equidigital number, since it uses as much as digits as its factorization.
31402013371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 31402013371 its reverse (17331020413), we get a palindrome (48733033784).
The spelling of 31402013371 in words is "thirty-one billion, four hundred two million, thirteen thousand, three hundred seventy-one".
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