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31404013041 = 340012616347
BaseRepresentation
bin11101001111110100…
…110011010111110001
310000001121012011012010
4131033310303113301
51003303411404131
622232104553133
72161135464222
oct351764632761
9100047164163
1031404013041
1112355823895
1261051827a9
132c6621a34b
14173cac3249
15c3c012b46
hex74fd335f1

31404013041 has 8 divisors (see below), whose sum is σ = 41882498784. Its totient is φ = 20930768000.

The previous prime is 31404012973. The next prime is 31404013063. The reversal of 31404013041 is 14031040413.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31404013041 - 217 = 31403881969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31404012999 and 31404013017.

It is not an unprimeable number, because it can be changed into a prime (31404013441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1296171 + ... + 1320176.

It is an arithmetic number, because the mean of its divisors is an integer number (5235312348).

Almost surely, 231404013041 is an apocalyptic number.

It is an amenable number.

31404013041 is a deficient number, since it is larger than the sum of its proper divisors (10478485743).

31404013041 is a wasteful number, since it uses less digits than its factorization.

31404013041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2620351.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 31404013041 its reverse (14031040413), we get a palindrome (45435053454).

The spelling of 31404013041 in words is "thirty-one billion, four hundred four million, thirteen thousand, forty-one".

Divisors: 1 3 4001 12003 2616347 7849041 10468004347 31404013041