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314103023131 = 1312397733001
BaseRepresentation
bin1001001001000011111…
…11111100011000011011
31010000202101020211111011
410210201333330120123
520121240333220011
6400144045514351
731456523434012
oct4444177743033
91100671224434
10314103023131
11111234a71317
1250a605729b7
132380989c301
14112ba195a79
158285892621
hex4921ffc61b

314103023131 has 4 divisors (see below), whose sum is σ = 316500756264. Its totient is φ = 311705290000.

The previous prime is 314103023057. The next prime is 314103023149. The reversal of 314103023131 is 131320301413.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 314103023131 - 221 = 314100925979 is a prime.

It is a super-2 number, since 2×3141030231312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (314103033131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1198866370 + ... + 1198866631.

It is an arithmetic number, because the mean of its divisors is an integer number (79125189066).

Almost surely, 2314103023131 is an apocalyptic number.

314103023131 is a deficient number, since it is larger than the sum of its proper divisors (2397733133).

314103023131 is a wasteful number, since it uses less digits than its factorization.

314103023131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2397733132.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 314103023131 its reverse (131320301413), we get a palindrome (445423324544).

The spelling of 314103023131 in words is "three hundred fourteen billion, one hundred three million, twenty-three thousand, one hundred thirty-one".

Divisors: 1 131 2397733001 314103023131