Base | Representation |
---|---|
bin | 101101101101010101001… |
… | …011110001010100011111 |
3 | 102010021121012011222211120 |
4 | 231231111023301110133 |
5 | 402430332330223320 |
6 | 10402551211422023 |
7 | 442635103351305 |
oct | 55552513612437 |
9 | 12107535158746 |
10 | 3141050242335 |
11 | 1001125a7a495 |
12 | 42890b454913 |
13 | 19a279b70865 |
14 | ac055bd0275 |
15 | 56a8c76d440 |
hex | 2db552f151f |
3141050242335 has 16 divisors (see below), whose sum is σ = 5025851971200. Its totient is φ = 1675169601440.
The previous prime is 3141050242307. The next prime is 3141050242373. The reversal of 3141050242335 is 5332420501413.
It is not a de Polignac number, because 3141050242335 - 27 = 3141050242207 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3141050242296 and 3141050242305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3118785 + ... + 4001114.
It is an arithmetic number, because the mean of its divisors is an integer number (314115748200).
Almost surely, 23141050242335 is an apocalyptic number.
3141050242335 is a deficient number, since it is larger than the sum of its proper divisors (1884801728865).
3141050242335 is a wasteful number, since it uses less digits than its factorization.
3141050242335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7149318.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 3141050242335 its reverse (5332420501413), we get a palindrome (8473470743748).
The spelling of 3141050242335 in words is "three trillion, one hundred forty-one billion, fifty million, two hundred forty-two thousand, three hundred thirty-five".
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