3141114121 has 4 divisors (see below), whose sum is σ = 3141234432. Its totient is φ = 3140993812.

The previous prime is 3141114103. The next prime is 3141114127. The reversal of 3141114121 is 1214111413.

3141114121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 3141114121 - 2⁹ = 3141113609 is a prime.

It is a super-2 number, since 2×3141114121² = 19733195842291205282, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3141114127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2701 + ... + 79306.

It is an arithmetic number, because the mean of its divisors is an integer number (785308608).

Almost surely, 2^3141114121 is an apocalyptic number.

It is an amenable number.

3141114121 is a deficient number, since it is larger than the sum of its proper divisors (120311).

3141114121 is an equidigital number, since it uses as much as digits as its factorization.

3141114121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 120310.

The product of its digits is 96, while the sum is 19.

The square root of 3141114121 is about 56045.6431937399. The cubic root of 3141114121 is about 1464.5175207658.

Adding to 3141114121 its reverse (1214111413), we get a palindrome (4355225534).

It can be divided in two parts, 314111412 and 1, that added together give a palindrome (314111413).

The spelling of 3141114121 in words is "three billion, one hundred forty-one million, one hundred fourteen thousand, one hundred twenty-one".