Base | Representation |
---|---|
bin | 101101101101011001011… |
… | …111001100011100001100 |
3 | 102010021210020001011120000 |
4 | 231231121133030130030 |
5 | 402431004321134040 |
6 | 10403002311124300 |
7 | 442636641142032 |
oct | 55553137143414 |
9 | 12107706034500 |
10 | 3141122443020 |
11 | 1001162803981 |
12 | 42892b673690 |
13 | 19a28baccc63 |
14 | ac061626552 |
15 | 56a93c81130 |
hex | 2db597cc70c |
3141122443020 has 240 divisors, whose sum is σ = 10408240432128. Its totient is φ = 791760251520.
The previous prime is 3141122442973. The next prime is 3141122443027. The reversal of 3141122443020 is 203442211413.
3141122443020 is a `hidden beast` number, since 3 + 1 + 4 + 1 + 1 + 224 + 430 + 2 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is not an unprimeable number, because it can be changed into a prime (3141122443027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 1432167 + ... + 2886753.
Almost surely, 23141122443020 is an apocalyptic number.
3141122443020 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 3141122443020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5204120216064).
3141122443020 is an abundant number, since it is smaller than the sum of its proper divisors (7267117989108).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3141122443020 is a wasteful number, since it uses less digits than its factorization.
3141122443020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1454682 (or 1454671 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 3141122443020 its reverse (203442211413), we get a palindrome (3344564654433).
The spelling of 3141122443020 in words is "three trillion, one hundred forty-one billion, one hundred twenty-two million, four hundred forty-three thousand, twenty".
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