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31413111433 = 1114871920469
BaseRepresentation
bin11101010000010111…
…100000101010001001
310000002020022101211121
4131100113200222021
51003313224031213
622233031555241
72161306020154
oct352027405211
9100066271747
1031413111433
111235a978620
12610822bb21
132c68084702
14173ddb0c9b
15c3cc0d88d
hex7505e0a89

31413111433 has 8 divisors (see below), whose sum is σ = 34291912320. Its totient is φ = 28538154480.

The previous prime is 31413111391. The next prime is 31413111437. The reversal of 31413111433 is 33411131413.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-31413111433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31413111398 and 31413111407.

It is not an unprimeable number, because it can be changed into a prime (31413111437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 943878 + ... + 976591.

It is an arithmetic number, because the mean of its divisors is an integer number (4286489040).

Almost surely, 231413111433 is an apocalyptic number.

It is an amenable number.

31413111433 is a deficient number, since it is larger than the sum of its proper divisors (2878800887).

31413111433 is a wasteful number, since it uses less digits than its factorization.

31413111433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1921967.

The product of its digits is 1296, while the sum is 25.

Adding to 31413111433 its reverse (33411131413), we get a palindrome (64824242846).

The spelling of 31413111433 in words is "thirty-one billion, four hundred thirteen million, one hundred eleven thousand, four hundred thirty-three".

Divisors: 1 11 1487 16357 1920469 21125159 2855737403 31413111433