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31431223433114 = 215715611716557
BaseRepresentation
bin1110010010110001001101…
…11010000101011110011010
311010021210111000002022001122
413021120212322011132122
513104432121144324424
6150503145452245242
76422555006011421
oct711304672053632
9133253430068048
1031431223433114
11a0189a824381a
1236376b9170822
13146cc4aa1861b
147a93ca6b02b8
153978e917b45e
hex1c9626e8579a

31431223433114 has 4 divisors (see below), whose sum is σ = 47146835149674. Its totient is φ = 15715611716556.

The previous prime is 31431223433107. The next prime is 31431223433153. The reversal of 31431223433114 is 41133432213413.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 25421209383025 + 6010014050089 = 5041945^2 + 2451533^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7857805858277 + ... + 7857805858280.

Almost surely, 231431223433114 is an apocalyptic number.

31431223433114 is a deficient number, since it is larger than the sum of its proper divisors (15715611716560).

31431223433114 is a wasteful number, since it uses less digits than its factorization.

31431223433114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15715611716559.

The product of its digits is 62208, while the sum is 35.

Adding to 31431223433114 its reverse (41133432213413), we get a palindrome (72564655646527).

The spelling of 31431223433114 in words is "thirty-one trillion, four hundred thirty-one billion, two hundred twenty-three million, four hundred thirty-three thousand, one hundred fourteen".

Divisors: 1 2 15715611716557 31431223433114