Base | Representation |
---|---|
bin | 1110010010110001001101… |
… | …11010000101011110011010 |
3 | 11010021210111000002022001122 |
4 | 13021120212322011132122 |
5 | 13104432121144324424 |
6 | 150503145452245242 |
7 | 6422555006011421 |
oct | 711304672053632 |
9 | 133253430068048 |
10 | 31431223433114 |
11 | a0189a824381a |
12 | 36376b9170822 |
13 | 146cc4aa1861b |
14 | 7a93ca6b02b8 |
15 | 3978e917b45e |
hex | 1c9626e8579a |
31431223433114 has 4 divisors (see below), whose sum is σ = 47146835149674. Its totient is φ = 15715611716556.
The previous prime is 31431223433107. The next prime is 31431223433153. The reversal of 31431223433114 is 41133432213413.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 25421209383025 + 6010014050089 = 5041945^2 + 2451533^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7857805858277 + ... + 7857805858280.
Almost surely, 231431223433114 is an apocalyptic number.
31431223433114 is a deficient number, since it is larger than the sum of its proper divisors (15715611716560).
31431223433114 is a wasteful number, since it uses less digits than its factorization.
31431223433114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15715611716559.
The product of its digits is 62208, while the sum is 35.
Adding to 31431223433114 its reverse (41133432213413), we get a palindrome (72564655646527).
The spelling of 31431223433114 in words is "thirty-one trillion, four hundred thirty-one billion, two hundred twenty-three million, four hundred thirty-three thousand, one hundred fourteen".
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