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3143302055 = 5628660411
BaseRepresentation
bin1011101101011010…
…1111101110100111
322010001200021210122
42323112233232213
522414141131210
61235523512155
7140615424635
oct27326575647
98101607718
103143302055
1113733483a3
1273882865b
133b12a985a
1421b66a355
15135e4db55
hexbb5afba7

3143302055 has 4 divisors (see below), whose sum is σ = 3771962472. Its totient is φ = 2514641640.

The previous prime is 3143302039. The next prime is 3143302079. The reversal of 3143302055 is 5502033413.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5502033413 = 8576420109.

It is not a de Polignac number, because 3143302055 - 24 = 3143302039 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 314330201 + ... + 314330210.

It is an arithmetic number, because the mean of its divisors is an integer number (942990618).

Almost surely, 23143302055 is an apocalyptic number.

3143302055 is a deficient number, since it is larger than the sum of its proper divisors (628660417).

3143302055 is an equidigital number, since it uses as much as digits as its factorization.

3143302055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 628660416.

The product of its (nonzero) digits is 5400, while the sum is 26.

The square root of 3143302055 is about 56065.1590116357. The cubic root of 3143302055 is about 1464.8574770008.

Adding to 3143302055 its reverse (5502033413), we get a palindrome (8645335468).

The spelling of 3143302055 in words is "three billion, one hundred forty-three million, three hundred two thousand, fifty-five".

Divisors: 1 5 628660411 3143302055