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314331300219 = 3104777100073
BaseRepresentation
bin1001001001011111001…
…10110000000101111011
31010001100021210111210010
410210233212300011323
520122222303101334
6400222442353003
731465264652616
oct4445746600573
91101307714703
10314331300219
11111341908272
1250b04abb763
1323844c77301
14112dc61917d
15829a9350e9
hex492f9b017b

314331300219 has 4 divisors (see below), whose sum is σ = 419108400296. Its totient is φ = 209554200144.

The previous prime is 314331300203. The next prime is 314331300229. The reversal of 314331300219 is 912003133413.

314331300219 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 314331300219 - 24 = 314331300203 is a prime.

It is a super-2 number, since 2×3143313002192 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (314331300229) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52388550034 + ... + 52388550039.

It is an arithmetic number, because the mean of its divisors is an integer number (104777100074).

Almost surely, 2314331300219 is an apocalyptic number.

314331300219 is a deficient number, since it is larger than the sum of its proper divisors (104777100077).

314331300219 is a wasteful number, since it uses less digits than its factorization.

314331300219 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104777100076.

The product of its (nonzero) digits is 5832, while the sum is 30.

The spelling of 314331300219 in words is "three hundred fourteen billion, three hundred thirty-one million, three hundred thousand, two hundred nineteen".

Divisors: 1 3 104777100073 314331300219