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314334002113 = 647485833079
BaseRepresentation
bin1001001001011111100…
…01000011101111000001
31010001100110212210002021
410210233301003233001
520122224001031423
6400223020321441
731465326635065
oct4445761035701
91101313783067
10314334002113
1111134339323a
1250b059a3281
13238456b2071
14112dcb1daa5
15829acba95d
hex492fc43bc1

314334002113 has 4 divisors (see below), whose sum is σ = 314819835840. Its totient is φ = 313848168388.

The previous prime is 314334001973. The next prime is 314334002179. The reversal of 314334002113 is 311200433413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 314334002113 - 221 = 314331904961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (314334002183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 242915893 + ... + 242917186.

It is an arithmetic number, because the mean of its divisors is an integer number (78704958960).

Almost surely, 2314334002113 is an apocalyptic number.

It is an amenable number.

314334002113 is a deficient number, since it is larger than the sum of its proper divisors (485833727).

314334002113 is an equidigital number, since it uses as much as digits as its factorization.

314334002113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 485833726.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 314334002113 its reverse (311200433413), we get a palindrome (625534435526).

The spelling of 314334002113 in words is "three hundred fourteen billion, three hundred thirty-four million, two thousand, one hundred thirteen".

Divisors: 1 647 485833079 314334002113