Base | Representation |
---|---|
bin | 1110010010110110100111… |
… | …01100000011001100010011 |
3 | 11010022001222000122112021212 |
4 | 13021123103230003030103 |
5 | 13110004040241241430 |
6 | 150504345243210335 |
7 | 6423016565145230 |
oct | 711332354031423 |
9 | 133261860575255 |
10 | 31434122212115 |
11 | a01a155559347 |
12 | 3638187b169ab |
13 | 14702c044c67c |
14 | 7a95c3688787 |
15 | 397a188c8b95 |
hex | 1c96d3b03313 |
31434122212115 has 16 divisors (see below), whose sum is σ = 43110253682688. Its totient is φ = 21554526478176.
The previous prime is 31434122212063. The next prime is 31434122212123. The reversal of 31434122212115 is 51121222143413.
It is a cyclic number.
It is not a de Polignac number, because 31434122212115 - 232 = 31429827244819 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3689867 + ... + 8745476.
It is an arithmetic number, because the mean of its divisors is an integer number (2694390855168).
Almost surely, 231434122212115 is an apocalyptic number.
31434122212115 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
31434122212115 is a deficient number, since it is larger than the sum of its proper divisors (11676131470573).
31434122212115 is a wasteful number, since it uses less digits than its factorization.
31434122212115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12507578.
The product of its digits is 11520, while the sum is 32.
Adding to 31434122212115 its reverse (51121222143413), we get a palindrome (82555344355528).
The spelling of 31434122212115 in words is "thirty-one trillion, four hundred thirty-four billion, one hundred twenty-two million, two hundred twelve thousand, one hundred fifteen".
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