Base | Representation |
---|---|
bin | 1110010010111000011101… |
… | …10101100010011100010001 |
3 | 11010022011112011220210000201 |
4 | 13021130032311202130101 |
5 | 13110013103311231103 |
6 | 150505031532415201 |
7 | 6423053305005511 |
oct | 711341665423421 |
9 | 133264464823021 |
10 | 31435114555153 |
11 | a01a614722361 |
12 | 3638404317501 |
13 | 147041ac085ba |
14 | 7a96793a1841 |
15 | 397a75a9651d |
hex | 1c970ed62711 |
31435114555153 has 4 divisors (see below), whose sum is σ = 31435128313060. Its totient is φ = 31435100797248.
The previous prime is 31435114555147. The next prime is 31435114555181. The reversal of 31435114555153 is 35155541153413.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 27133920614529 + 4301193940624 = 5209023^2 + 2073932^2 .
It is a cyclic number.
It is not a de Polignac number, because 31435114555153 - 217 = 31435114424081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31435114355153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2538900 + ... + 8325637.
It is an arithmetic number, because the mean of its divisors is an integer number (7858782078265).
Almost surely, 231435114555153 is an apocalyptic number.
It is an amenable number.
31435114555153 is a deficient number, since it is larger than the sum of its proper divisors (13757907).
31435114555153 is a wasteful number, since it uses less digits than its factorization.
31435114555153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13757906.
The product of its digits is 1350000, while the sum is 46.
The spelling of 31435114555153 in words is "thirty-one trillion, four hundred thirty-five billion, one hundred fourteen million, five hundred fifty-five thousand, one hundred fifty-three".
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