Base | Representation |
---|---|
bin | 101101101111101010001… |
… | …100001011010100111101 |
3 | 102010112001102012200000011 |
4 | 231233222030023110331 |
5 | 403000442314412140 |
6 | 10404043233303221 |
7 | 443054050301530 |
oct | 55575214132475 |
9 | 12115042180004 |
10 | 3143550154045 |
11 | 1002199123124 |
12 | 4292a8704b11 |
13 | 19a587a6ba62 |
14 | ac211c1aa17 |
15 | 56b86e7ccea |
hex | 2dbea30b53d |
3143550154045 has 16 divisors (see below), whose sum is σ = 4319624373120. Its totient is φ = 2151342310464.
The previous prime is 3143550153937. The next prime is 3143550154079. The reversal of 3143550154045 is 5404510553413.
It is a cyclic number.
It is not a de Polignac number, because 3143550154045 - 211 = 3143550151997 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3143550153989 and 3143550154007.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 88209807 + ... + 88245436.
It is an arithmetic number, because the mean of its divisors is an integer number (269976523320).
Almost surely, 23143550154045 is an apocalyptic number.
3143550154045 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
3143550154045 is a deficient number, since it is larger than the sum of its proper divisors (1176074219075).
3143550154045 is a wasteful number, since it uses less digits than its factorization.
3143550154045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 176455764.
The product of its (nonzero) digits is 360000, while the sum is 40.
The spelling of 3143550154045 in words is "three trillion, one hundred forty-three billion, five hundred fifty million, one hundred fifty-four thousand, forty-five".
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