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314387840471041 = 2631195391028407
BaseRepresentation
bin100011101111011110001111…
…1100011011001000000000001
31112020011011222011010211200001
41013132330133203121000001
5312201412244130033131
63032351440254400001
7123135525523560001
oct10736743743310001
91466134864124601
10314387840471041
11911a0152965417
122b316577800001
131065685277833c
14578c64a1a0001
152652e388c2261
hex11def1f8d9001

314387840471041 has 4 divisors (see below), whose sum is σ = 315583231499712. Its totient is φ = 313192449442372.

The previous prime is 314387840471021. The next prime is 314387840471063. The reversal of 314387840471041 is 140174048783413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-314387840471041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (314387840471021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 597695513941 + ... + 597695514466.

It is an arithmetic number, because the mean of its divisors is an integer number (78895807874928).

Almost surely, 2314387840471041 is an apocalyptic number.

It is an amenable number.

314387840471041 is a deficient number, since it is larger than the sum of its proper divisors (1195391028671).

314387840471041 is a wasteful number, since it uses less digits than its factorization.

314387840471041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1195391028670.

The product of its (nonzero) digits is 7225344, while the sum is 55.

The spelling of 314387840471041 in words is "three hundred fourteen trillion, three hundred eighty-seven billion, eight hundred forty million, four hundred seventy-one thousand, forty-one".

Divisors: 1 263 1195391028407 314387840471041