Base | Representation |
---|---|
bin | 100011101111011110001111… |
… | …1100011011001000000010111 |
3 | 1112020011011222011010211200212 |
4 | 1013132330133203121000113 |
5 | 312201412244130033223 |
6 | 3032351440254400035 |
7 | 123135525523560032 |
oct | 10736743743310027 |
9 | 1466134864124625 |
10 | 314387840471063 |
11 | 911a0152965437 |
12 | 2b31657780001b |
13 | 10656852778358 |
14 | 578c64a1a0019 |
15 | 2652e388c2278 |
hex | 11def1f8d9017 |
314387840471063 has 2 divisors, whose sum is σ = 314387840471064. Its totient is φ = 314387840471062.
The previous prime is 314387840471021. The next prime is 314387840471071. The reversal of 314387840471063 is 360174048783413.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 314387840471063 - 212 = 314387840466967 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 314387840470993 and 314387840471011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (314387840470063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157193920235531 + 157193920235532.
It is an arithmetic number, because the mean of its divisors is an integer number (157193920235532).
Almost surely, 2314387840471063 is an apocalyptic number.
314387840471063 is a deficient number, since it is larger than the sum of its proper divisors (1).
314387840471063 is an equidigital number, since it uses as much as digits as its factorization.
314387840471063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32514048, while the sum is 59.
The spelling of 314387840471063 in words is "three hundred fourteen trillion, three hundred eighty-seven billion, eight hundred forty million, four hundred seventy-one thousand, sixty-three".
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