314412130401331 has 4 divisors (see below), whose sum is σ = 321101750197152. Its totient is φ = 307722510605512.

The previous prime is 314412130401311. The next prime is 314412130401349. The reversal of 314412130401331 is 133104031214413.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 314412130401331 - 2⁴³ = 305616037379123 is a prime.

It is a super-2 number, since 2×314412130401331² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 314412130401293 and 314412130401302.

It is not an unprimeable number, because it can be changed into a prime (314412130401311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3344809897840 + ... + 3344809897933.

It is an arithmetic number, because the mean of its divisors is an integer number (80275437549288).

Almost surely, 2^{314412130401331} is an apocalyptic number.

314412130401331 is a deficient number, since it is larger than the sum of its proper divisors (6689619795821).

314412130401331 is an equidigital number, since it uses as much as digits as its factorization.

314412130401331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6689619795820.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 314412130401331 its reverse (133104031214413), we get a palindrome (447516161615744).

The spelling of 314412130401331 in words is "three hundred fourteen trillion, four hundred twelve billion, one hundred thirty million, four hundred one thousand, three hundred thirty-one".