Base | Representation |
---|---|
bin | 1110010011000011110101… |
… | …10101011101001001110001 |
3 | 11010022202021210002200022011 |
4 | 13021201322311131021301 |
5 | 13110113110142040423 |
6 | 150511521524242521 |
7 | 6423360530453032 |
oct | 711417265351161 |
9 | 133282253080264 |
10 | 31441221440113 |
11 | a022168917421 |
12 | 3639629540441 |
13 | 1470b821888b4 |
14 | 7a9a98474a89 |
15 | 397cd1c93b0d |
hex | 1c987ad5d271 |
31441221440113 has 24 divisors (see below), whose sum is σ = 35212741156800. Its totient is φ = 28008453740256.
The previous prime is 31441221440107. The next prime is 31441221440119. The reversal of 31441221440113 is 31104412214413.
It is an interprime number because it is at equal distance from previous prime (31441221440107) and next prime (31441221440119).
It is a de Polignac number, because none of the positive numbers 2k-31441221440113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31441221440119) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 31601058 + ... + 32580811.
It is an arithmetic number, because the mean of its divisors is an integer number (1467197548200).
Almost surely, 231441221440113 is an apocalyptic number.
It is an amenable number.
31441221440113 is a deficient number, since it is larger than the sum of its proper divisors (3771519716687).
31441221440113 is a wasteful number, since it uses less digits than its factorization.
31441221440113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64181989 (or 64181970 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 31441221440113 its reverse (31104412214413), we get a palindrome (62545633654526).
The spelling of 31441221440113 in words is "thirty-one trillion, four hundred forty-one billion, two hundred twenty-one million, four hundred forty thousand, one hundred thirteen".
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