Base | Representation |
---|---|
bin | 11101010010001010… |
… | …000100001100011011 |
3 | 10000011022211002012201 |
4 | 131102022010030123 |
5 | 1003343421011103 |
6 | 22240023351031 |
7 | 2162122202122 |
oct | 352212041433 |
9 | 100138732181 |
10 | 31443141403 |
11 | 12375919583 |
12 | 61162b2477 |
13 | 2c7136a21b |
14 | 1743d8aab9 |
15 | c4069151d |
hex | 75228431b |
31443141403 has 4 divisors (see below), whose sum is σ = 31446573160. Its totient is φ = 31439709648.
The previous prime is 31443141343. The next prime is 31443141419. The reversal of 31443141403 is 30414134413.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31443141403 is a prime.
It is a super-4 number, since 4×314431414034 (a number of 43 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31443141493) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1702098 + ... + 1720471.
It is an arithmetic number, because the mean of its divisors is an integer number (7861643290).
Almost surely, 231443141403 is an apocalyptic number.
31443141403 is a deficient number, since it is larger than the sum of its proper divisors (3431757).
31443141403 is an equidigital number, since it uses as much as digits as its factorization.
31443141403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3431756.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 31443141403 its reverse (30414134413), we get a palindrome (61857275816).
The spelling of 31443141403 in words is "thirty-one billion, four hundred forty-three million, one hundred forty-one thousand, four hundred three".
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