31450540361341 has 4 divisors (see below), whose sum is σ = 31450818401884. Its totient is φ = 31450262320800.

The previous prime is 31450540361329. The next prime is 31450540361353. The reversal of 31450540361341 is 14316304505413.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (31450540361329) and next prime (31450540361353).

It can be written as a sum of positive squares in 2 ways, for example, as 22179861202500 + 9270679158841 = 4709550^2 + 3044779^2 .

It is a cyclic number.

It is not a de Polignac number, because 31450540361341 - 2⁵ = 31450540361309 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31450540361294 and 31450540361303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31450540361311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138850530 + ... + 139076851.

It is an arithmetic number, because the mean of its divisors is an integer number (7862704600471).

Almost surely, 2^{31450540361341} is an apocalyptic number.

It is an amenable number.

31450540361341 is a deficient number, since it is larger than the sum of its proper divisors (278040543).

31450540361341 is a wasteful number, since it uses less digits than its factorization.

31450540361341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 278040542.

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 31450540361341 its reverse (14316304505413), we get a palindrome (45766844866754).

The spelling of 31450540361341 in words is "thirty-one trillion, four hundred fifty billion, five hundred forty million, three hundred sixty-one thousand, three hundred forty-one".