Base | Representation |
---|---|
bin | 101101110001001001010… |
… | …001100100000001000101 |
3 | 102010200011120221122000000 |
4 | 231301021101210001011 |
5 | 403012224210321123 |
6 | 10404505421111513 |
7 | 443141430545511 |
oct | 55611121440105 |
9 | 12120146848000 |
10 | 3145145401413 |
11 | 1002937649084 |
12 | 4296729b8599 |
13 | 19a7803cc502 |
14 | ac323a35141 |
15 | 56c2c03db43 |
hex | 2dc49464045 |
3145145401413 has 56 divisors (see below), whose sum is σ = 4781764545792. Its totient is φ = 2067345695808.
The previous prime is 3145145401397. The next prime is 3145145401421. The reversal of 3145145401413 is 3141045415413.
3145145401413 is a `hidden beast` number, since 3 + 14 + 51 + 454 + 0 + 141 + 3 = 666.
It is not a de Polignac number, because 3145145401413 - 24 = 3145145401397 is a prime.
It is a super-3 number, since 3×31451454014133 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3145145401483) by changing a digit.
It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 193861420 + ... + 193877642.
Almost surely, 23145145401413 is an apocalyptic number.
It is an amenable number.
3145145401413 is a deficient number, since it is larger than the sum of its proper divisors (1636619144379).
3145145401413 is an equidigital number, since it uses as much as digits as its factorization.
3145145401413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19957 (or 19942 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 36.
The spelling of 3145145401413 in words is "three trillion, one hundred forty-five billion, one hundred forty-five million, four hundred one thousand, four hundred thirteen".
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