314540141413 has 4 divisors (see below), whose sum is σ = 315613657548. Its totient is φ = 313466625280.

The previous prime is 314540141407. The next prime is 314540141423. The reversal of 314540141413 is 314141045413.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 149458013604 + 165082127809 = 386598^2 + 406303^2 .

It is a cyclic number.

It is not a de Polignac number, because 314540141413 - 2²⁹ = 314003270501 is a prime.

It is a super-2 number, since 2×314540141413² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (314540141423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 536757628 + ... + 536758213.

It is an arithmetic number, because the mean of its divisors is an integer number (78903414387).

Almost surely, 2^314540141413 is an apocalyptic number.

It is an amenable number.

314540141413 is a deficient number, since it is larger than the sum of its proper divisors (1073516135).

314540141413 is a wasteful number, since it uses less digits than its factorization.

314540141413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1073516134.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 314540141413 its reverse (314141045413), we get a palindrome (628681186826).

The spelling of 314540141413 in words is "three hundred fourteen billion, five hundred forty million, one hundred forty-one thousand, four hundred thirteen".