Base | Representation |
---|---|
bin | 1110010011011101100011… |
… | …11000111110100001011101 |
3 | 11010101001221010100210212110 |
4 | 13021232301320332201131 |
5 | 13110324400140340442 |
6 | 150522124042024233 |
7 | 6424356652415064 |
oct | 711566170764135 |
9 | 133331833323773 |
10 | 31455030011997 |
11 | a0280044578a9 |
12 | 3640241aa8079 |
13 | 1472272c21ca7 |
14 | 7aa60835b1db |
15 | 39833e1b269c |
hex | 1c9bb1e3e85d |
31455030011997 has 4 divisors (see below), whose sum is σ = 41940040016000. Its totient is φ = 20970020007996.
The previous prime is 31455030011939. The next prime is 31455030012001. The reversal of 31455030011997 is 79911003055413.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 31455030011997 - 210 = 31455030010973 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31455030011917) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5242505001997 + ... + 5242505002002.
It is an arithmetic number, because the mean of its divisors is an integer number (10485010004000).
Almost surely, 231455030011997 is an apocalyptic number.
It is an amenable number.
31455030011997 is a deficient number, since it is larger than the sum of its proper divisors (10485010004003).
31455030011997 is a wasteful number, since it uses less digits than its factorization.
31455030011997 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10485010004002.
The product of its (nonzero) digits is 510300, while the sum is 48.
The spelling of 31455030011997 in words is "thirty-one trillion, four hundred fifty-five billion, thirty million, eleven thousand, nine hundred ninety-seven".
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