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3145535241113 = 13722960111249
BaseRepresentation
bin101101110001100000100…
…000101011101110011001
3102010201011202111112112102
4231301200200223232121
5403014024010203423
610405012224453145
7443154203252426
oct55614040535631
912121152445472
103145535241113
111003017704451
1242976147a1b5
1319a8130c42a5
14ac35d712d4d
1556c51396c28
hex2dc6082bb99

3145535241113 has 4 divisors (see below), whose sum is σ = 3168495352500. Its totient is φ = 3122575129728.

The previous prime is 3145535241097. The next prime is 3145535241181. The reversal of 3145535241113 is 3111425355413.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2355939498649 + 789595742464 = 1534907^2 + 888592^2 .

It is a cyclic number.

It is not a de Polignac number, because 3145535241113 - 24 = 3145535241097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3145535241713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11480055488 + ... + 11480055761.

It is an arithmetic number, because the mean of its divisors is an integer number (792123838125).

Almost surely, 23145535241113 is an apocalyptic number.

It is an amenable number.

3145535241113 is a deficient number, since it is larger than the sum of its proper divisors (22960111387).

3145535241113 is a wasteful number, since it uses less digits than its factorization.

3145535241113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22960111386.

The product of its digits is 108000, while the sum is 38.

The spelling of 3145535241113 in words is "three trillion, one hundred forty-five billion, five hundred thirty-five million, two hundred forty-one thousand, one hundred thirteen".

Divisors: 1 137 22960111249 3145535241113