Base | Representation |
---|---|
bin | 101101110011111011111… |
… | …000100010000110000111 |
3 | 102010221220102111122210220 |
4 | 231303323320202012013 |
5 | 403034343320232412 |
6 | 10410123023515423 |
7 | 443305615103556 |
oct | 55637370420607 |
9 | 12127812448726 |
10 | 3148141961607 |
11 | 100413507a105 |
12 | 42a16a458b73 |
13 | 19ab3a17b156 |
14 | ac5299c3d9d |
15 | 56d5515368c |
hex | 2dcfbe22187 |
3148141961607 has 16 divisors (see below), whose sum is σ = 4444836226560. Its totient is φ = 1975126753152.
The previous prime is 3148141961579. The next prime is 3148141961633. The reversal of 3148141961607 is 7061691418413.
It is not a de Polignac number, because 3148141961607 - 27 = 3148141961479 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a self number, because there is not a number n which added to its sum of digits gives 3148141961607.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3148141961677) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2208733 + ... + 3342870.
It is an arithmetic number, because the mean of its divisors is an integer number (277802264160).
Almost surely, 23148141961607 is an apocalyptic number.
3148141961607 is a deficient number, since it is larger than the sum of its proper divisors (1296694264953).
3148141961607 is a wasteful number, since it uses less digits than its factorization.
3148141961607 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5562742.
The product of its (nonzero) digits is 870912, while the sum is 51.
The spelling of 3148141961607 in words is "three trillion, one hundred forty-eight billion, one hundred forty-one million, nine hundred sixty-one thousand, six hundred seven".
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