314831157 has 4 divisors (see below), whose sum is σ = 419774880. Its totient is φ = 209887436.

The previous prime is 314831149. The next prime is 314831161. The reversal of 314831157 is 751138413.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 751138413 = 3 ⋅250379471.

It is a cyclic number.

It is not a de Polignac number, because 314831157 - 2³ = 314831149 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (314831117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52471857 + ... + 52471862.

It is an arithmetic number, because the mean of its divisors is an integer number (104943720).

Almost surely, 2^314831157 is an apocalyptic number.

It is an amenable number.

314831157 is a deficient number, since it is larger than the sum of its proper divisors (104943723).

314831157 is a wasteful number, since it uses less digits than its factorization.

314831157 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 104943722.

The product of its digits is 10080, while the sum is 33.

The square root of 314831157 is about 17743.4820990695. The cubic root of 314831157 is about 680.2876212624.

It can be divided in two parts, 31483 and 1157, that added together give a triangular number (32640 = T₂₅₅).

The spelling of 314831157 in words is "three hundred fourteen million, eight hundred thirty-one thousand, one hundred fifty-seven".