31490113 has 4 divisors (see below), whose sum is σ = 31502548. Its totient is φ = 31477680.

The previous prime is 31490099. The next prime is 31490119. The reversal of 31490113 is 31109413.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 31109413 = 659 ⋅47207.

It can be written as a sum of positive squares in 2 ways, for example, as 8334769 + 23155344 = 2887^2 + 4812^2 .

It is a cyclic number.

It is not a de Polignac number, because 31490113 - 2¹³ = 31481921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31490119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 906 + ... + 7987.

It is an arithmetic number, because the mean of its divisors is an integer number (7875637).

Almost surely, 2^31490113 is an apocalyptic number.

It is an amenable number.

31490113 is a deficient number, since it is larger than the sum of its proper divisors (12435).

31490113 is an equidigital number, since it uses as much as digits as its factorization.

31490113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12434.

The product of its (nonzero) digits is 324, while the sum is 22.

The square root of 31490113 is about 5611.6052070687. The cubic root of 31490113 is about 315.7849341779.

Adding to 31490113 its reverse (31109413), we get a palindrome (62599526).

The spelling of 31490113 in words is "thirty-one million, four hundred ninety thousand, one hundred thirteen".