Base | Representation |
---|---|
bin | 101101110101101011001… |
… | …110100110000111110101 |
3 | 102011010201121120200000201 |
4 | 231311223032212013311 |
5 | 403102210031004440 |
6 | 10411032234440501 |
7 | 443403120233161 |
oct | 55655316460765 |
9 | 12133647520021 |
10 | 3150010016245 |
11 | 1004a03596214 |
12 | 42a5abb93131 |
13 | 19b0771a8421 |
14 | ac665b33ca1 |
15 | 56e1415119a |
hex | 2dd6b3a61f5 |
3150010016245 has 8 divisors (see below), whose sum is σ = 3978960020640. Its totient is φ = 2387376012240.
The previous prime is 3150010016233. The next prime is 3150010016333. The reversal of 3150010016245 is 5426100100513.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3150010016245 - 241 = 950986760693 is a prime.
It is a super-3 number, since 3×31500100162453 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16578999991 + ... + 16579000180.
It is an arithmetic number, because the mean of its divisors is an integer number (497370002580).
Almost surely, 23150010016245 is an apocalyptic number.
It is an amenable number.
3150010016245 is a deficient number, since it is larger than the sum of its proper divisors (828950004395).
3150010016245 is a wasteful number, since it uses less digits than its factorization.
3150010016245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33158000195.
The product of its (nonzero) digits is 3600, while the sum is 28.
Adding to 3150010016245 its reverse (5426100100513), we get a palindrome (8576110116758).
The spelling of 3150010016245 in words is "three trillion, one hundred fifty billion, ten million, sixteen thousand, two hundred forty-five".
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