Base | Representation |
---|---|
bin | 1011101111000010… |
… | …1110100100001011 |
3 | 22010112111022201011 |
4 | 2323300232210023 |
5 | 22422412104120 |
6 | 1240325504351 |
7 | 141030343006 |
oct | 27360564413 |
9 | 8115438634 |
10 | 3150113035 |
11 | 137717a603 |
12 | 73ab720b7 |
13 | 3b2822a14 |
14 | 21c52053d |
15 | 136846c5a |
hex | bbc2e90b |
3150113035 has 8 divisors (see below), whose sum is σ = 3851459280. Its totient is φ = 2472541344.
The previous prime is 3150112991. The next prime is 3150113047. The reversal of 3150113035 is 5303110513.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3150113035 - 217 = 3149981963 is a prime.
It is a super-2 number, since 2×31501130352 = 19846424266553822450, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3150112997 and 3150113015.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5943345 + ... + 5943874.
It is an arithmetic number, because the mean of its divisors is an integer number (481432410).
Almost surely, 23150113035 is an apocalyptic number.
3150113035 is a deficient number, since it is larger than the sum of its proper divisors (701346245).
3150113035 is a wasteful number, since it uses less digits than its factorization.
3150113035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11887277.
The product of its (nonzero) digits is 675, while the sum is 22.
The square root of 3150113035 is about 56125.8677883915. The cubic root of 3150113035 is about 1465.9147428157.
Adding to 3150113035 its reverse (5303110513), we get a palindrome (8453223548).
The spelling of 3150113035 in words is "three billion, one hundred fifty million, one hundred thirteen thousand, thirty-five".
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