Base | Representation |
---|---|
bin | 101101110101111001100… |
… | …010010000100111010011 |
3 | 102011011100100020202020202 |
4 | 231311321202100213103 |
5 | 403103203003131201 |
6 | 10411112131325415 |
7 | 443412063425054 |
oct | 55657142204723 |
9 | 12134310222222 |
10 | 3150250052051 |
11 | 1005017033713 |
12 | 42a65845086b |
13 | 19b0b4b3c64b |
14 | ac68997872b |
15 | 56e2a267c6b |
hex | 2dd798909d3 |
3150250052051 has 16 divisors (see below), whose sum is σ = 3298686336000. Its totient is φ = 3005052117600.
The previous prime is 3150250051957. The next prime is 3150250052069. The reversal of 3150250052051 is 1502500520513.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3150250052051 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3150250052071) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1998041 + ... + 3208218.
It is an arithmetic number, because the mean of its divisors is an integer number (206167896000).
Almost surely, 23150250052051 is an apocalyptic number.
3150250052051 is a gapful number since it is divisible by the number (31) formed by its first and last digit.
3150250052051 is a deficient number, since it is larger than the sum of its proper divisors (148436283949).
3150250052051 is a wasteful number, since it uses less digits than its factorization.
3150250052051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5206570.
The product of its (nonzero) digits is 7500, while the sum is 29.
Adding to 3150250052051 its reverse (1502500520513), we get a palindrome (4652750572564).
The spelling of 3150250052051 in words is "three trillion, one hundred fifty billion, two hundred fifty million, fifty-two thousand, fifty-one".
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