Base | Representation |
---|---|
bin | 1001001010110010100… |
… | …00101001110010011101 |
3 | 1010010010222210202212111 |
4 | 10211121100221302131 |
5 | 20130140204302201 |
6 | 400420045234021 |
7 | 31521512044456 |
oct | 4453120516235 |
9 | 1103128722774 |
10 | 315030150301 |
11 | 111670341719 |
12 | 5107ab62911 |
13 | 239269a3179 |
14 | 1136737412d |
15 | 82dbe7bb51 |
hex | 4959429c9d |
315030150301 has 4 divisors (see below), whose sum is σ = 317296554400. Its totient is φ = 312763746204.
The previous prime is 315030150283. The next prime is 315030150317. The reversal of 315030150301 is 103051030513.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 103051030513 = 167 ⋅617072039.
It is a cyclic number.
It is not a de Polignac number, because 315030150301 - 29 = 315030149789 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (315030150601) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1133201841 + ... + 1133202118.
It is an arithmetic number, because the mean of its divisors is an integer number (79324138600).
Almost surely, 2315030150301 is an apocalyptic number.
It is an amenable number.
315030150301 is a deficient number, since it is larger than the sum of its proper divisors (2266404099).
315030150301 is a wasteful number, since it uses less digits than its factorization.
315030150301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2266404098.
The product of its (nonzero) digits is 675, while the sum is 22.
Adding to 315030150301 its reverse (103051030513), we get a palindrome (418081180814).
The spelling of 315030150301 in words is "three hundred fifteen billion, thirty million, one hundred fifty thousand, three hundred one".
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